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The uncertainty in momentum of an electr...

The uncertainty in momentum of an electron is `1 xx 10^-5 kg - m//s`. The uncertainty in its position will be `(h = 6.62 xx 10^-34 kg = m^2//s)`.

A

`1.05xx10^(-28)m`

B

`1.05xx10^(-26)m`

C

`5.27xx10^(-30)m`

D

`5.25xx10^(-28)m`

Text Solution

Verified by Experts

The correct Answer is:
C

(c) According to Heisenberg's uncertainty principle
`DeltapxxDeltax ge (h)/(4pi)`
Uncertainty in momentum
`Deltap=1xx10^(-5) kg m//s`
`1xx10^(-5)xxDeltax=(6.62xx10^(-34))/(4xx(22)/(7)) " " `(Given)
`Deltax=(6.62xx10^(-34)xx7)/(1xx10^(-5)xx4xx22)`
`=5.265xx10^(-30)m`
`=5.27xx10^(-30)m`
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