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x(1) = 5 sin omega t x(2) = 5 sin ...

`x_(1) = 5 sin omega t`
` x_(2) = 5 sin (omega t + 53^(@))`
`x_(3) = - 10 cos omega t`
Find amplitude of resultant SHM.

Text Solution

Verified by Experts

`x_(1) = 5sinomegat`
`x_(2) = 5 sin (omegat + 53^(@))`
`x_(3) = - 10 cos omegat`
we can write `x_(3) = 10 sin(omegat + 270^(@))`
Finding the resultant amplitude by vactor notation.

Resultant Amplitude `|R| = sqrt(8^(2) + 6^(2)) = 10` Ans.
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