A mass M is performing linear simple harmonic motion. Then correct graph for acceleration a and corresponding linear velocity v is

Options

A.
B.
C.
D.

Answer

B

Explanation

Velocity `v = omegasqrt(A^(2) - x^(2)) rArr v^(2) = omega^(2) - omega^(2)x^(2) …..(1)`
Acceleration `a = -omega^(2)x rArr a^(2) = omega^(4)x^(2) …….(2)`
`rArr (v^(2))/(omega^(2)A^(2)) + (a^(2))/(omega^(4)A^(2)) = 1`
`rArr v^(2) = -a^(2)(1)/(omega^(2)) + 1` its straight line with `-ve` slope and `+ve` intercept