Acceleration a versus time `t` graph of a body in `SHM` is given by a curve shown below. `T` is the time period Then corresponding graph between kinetic energy `KE` and time `t` is correctly represented by

Options

A.
B.
C.
D.

Answer

A

Explanation

`x = A cosomegat`
`K.E. = (1)/(2)k(A^(2) - x^(2)) = (1)/(2)kA^(2)sin^(2)omegat`
`= (1)/(2) kA^(2)((1-cos2omegat)/(2)) = (kA^(2))/(4) (1 - cos2omegat)`
Frequency of `K.E.` is double of acceleration