In the situation shown in figure, find the velocity of image.

Explanation

Along `x` direction, applying `v_(i) - v_(m) = -(v_(0) - v_(m))`
`v_(i) - (-5cos 30^(@)) = -(10 cos 60^(@) - (-5 cos 30^(@)))`
`:. V_(i) = -5(1 + sqrt(3)) m//s`
Along `y` directin `v_(0) = v_(i)`
`:. V_(i) = 10sin 60^(@) = 5sqrt(3) m//s`
`:.` Velocity of the image `= -5 (1 sqrt(3))hat(i) + 5 sqrt(3) hat(j) m//s`