Find the positon of final images formed.
(The gap shown in figure of negligible width)

Explanation

`(1)/(f_(eq)) = (1)/(10) - (2)/(10) = (-1)/(10)`
`rArr f_(eq) = -10 cm`
`(1)/(v) + (1)/(-20) = (1)/(-10)`
`rArr v = -20cm`
Hence image will be formed on the object itself.