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In the figure two triangular prism are s...

In the figure two triangular prism are shown each of refractive index `sqrt3` .
(a) Find the angle of incidence on the face `AB` for minimum deviation from the prism `ABC` ?
(b) Find the angle through which the prism `DCE` should be ratated about the edge passing through point `C` so that there should be minimum deviation from the system ?

Text Solution

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The correct Answer is:
(a)`i=60^(@);`(b)`60^(@)`

(a) At minimum deviation, `r_(1)=r_(2)=30^(@)`
`therefore` From Snell's law `mu=(sin i_(1))/(sin r_(1))` or `sqrt3=(sin i_(1))/(sin 30^(@))`
`therefore sin i_(1)=(sqrt3)/(2)` or `i_(1)=60^(@)`
(b) In the position shown below net deviation suffered by the ray of light should be minimum. Therefore, the second prism should be ratated by `60^(@)` (anticlockwise).
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Knowledge Check

  • A prism of apex angle A=60^@ has the refractive index mu=sqrt2. The angle of incidence for minimum deviation is

    A
    `30^@`
    B
    `45^@`
    C
    `60^@`
    D
    None of these
  • A prism has refractive index sqrt((3)/(2)) and refractive angle 90^@ . Find the minimum deviation produced by prism

    A
    `60^@`
    B
    `45^@`
    C
    `30^@`
    D
    `15^@`
  • An equilateral prism is made of a material of refractive index sqrt3 . The angle of minimum deviation for the prism is

    A
    `90^(@)`
    B
    `60^(@)`
    C
    `45^(@)`
    D
    `30^(@)`
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