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Let B(P) and B(Q) be the magnetic field ...

Let `B_(P)` and `B_(Q)` be the magnetic field produced by the wire `P` and `Q` which are placed symmetrically in a rectangular loop `ABCD` as shown in figure.Current in wire `P` is `I` directed inward and in `Q` is `2I` directed outwards.if `int_(A)^(B)vecB_(Q).vecdl=2mu_(0)` tesla meter,`int_(D)^(A)vecB_(P).vecdl=-2mu_(0)` tesla meter,&`int_(A)^(B)vecB_(P).vecdl=-mu_(0)` tesla meter tesla meter the value of `I` will be:

A

`8 A`

B

`4 A`

C

`5 A`

D

`6 A`

Text Solution

Verified by Experts

The correct Answer is:
D
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