Figure shows a circular wire-loop of radius `1/2 m` carrying a current `i`, placed in a perpendicular magnetic field `1/3 T`(a) Consider a small part `dl` of the wire.The force on this part of wire exerted by the magnetic field in the radially outward direction is `(idl)/N`.Then find value of `N` (b)Tension in the wire is `i/N`.Then find value of `N`.

Explanation

(a) Force an part of length `dl` of wire`=iBdl`
(b)`2Tsin (d theta)/2=iBdl`
`2Tsin (d theta)/2=iBdl`
`T=iBa`