Two identical conducting wires `AOB and COD` are placed at right angles to each other. The wire `AOB` carries an electric current `I_(1) and COD` carries a current `I_(2)`. The magnetic field on a point lying at a distance `d` from O, in a direction perpendicular to the plane of the wires `AOB and COD`, will be given by

Options

A. `mu_(0)/(2pi)((I_(1)+I_(2))/d)^(1//2)`
B. `mu_(0)/(2pid)(I_(1)^(2)+I_(2)^(2))^(1//2)`
C. `mu_(0)/(2pid)(I_(1)+I_(2))`
D. `mu_(0)/(2pid)(I_(1)^(2)+I_(2)^(2))`

Answer

2

Explanation

Magnetic field due to `AB` and `CD` are `(mu_(0)I_(1))/(2pid)` and `(mu_(0)I_(2))/(2pid)`respectively
`B_("net")=mu_(0)/(2pid)sqrt(I_(1)^(2)+I_(2)^(2))`