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Two long current carrying thin wires , b...

Two long current carrying thin wires , both with current `I`, are held by insulating threads of length `L` and are in equilibrium as shown in the gigure , With threads making an angle ` theta` with the vertical . If wires have mass ` lambda` per unit length then the value of `I` is :

A

`sinthetasqrt((pilambdagL)/(mu_(0)cos theta))`

B

`2sinthetasqrt((pilambdagL)/(mu_(0)cos theta))`

C

`2sqrt((pigL)/(mu_(0))tan theta`

D

`sqrt((pilambdagL)/(mu_(0))tan theta`

Text Solution

Verified by Experts

The correct Answer is:
2

`lambdalgsintheta=(mu_(0)I^(2))/(2pi(2L sin theta))lcos theta`
`2sinthetasqrt((lambdagmL)/(mu_(0)cos theta))=I`
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