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What is pOH of an aqueous solution with ...

What is `pOH` of an aqueous solution with `[H^(+)]=10^(-2)M` and `K_(w)=2xx10^(-12)`? Report your answer after dividing by `2` and round it off to the nearest whole number .

Text Solution

Verified by Experts

`[OH^(-)]=(2xx10^(-12))/(10^(-2))=2xx10^(-10)M`
`pOH=10-log2=9.7`
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