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If the equilibrium constant for the reac...

If the equilibrium constant for the reaction of weak acid HA with strong base is `10^(9)`, then pH of `0.1M` Na A is:

Text Solution

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`HA+NaOHhArrNaA+H_(2)O," "or" "HA+OH^(-)hArr A^(-)+H_(2)O`
`K_(eq)=10^(-9)=(1)/(K_(h))`(:. Hydrolysis is reverse of neutrailization.)
`A^(-)+H_(2)OhArr Ha+OH`
`[OH^(-)]=Ch=Csqrt((K_(h))/(C))=sqrt(CK_(h))=sqrt(0.1xx10^(-9))=10^(-5)M`
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