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For a 0.072 M NaSO(4) solution,select th...

For a `0.072 M NaSO_(4)` solution,select the incorrect option(s):`(K_(a_(1))` and `K_(a_(2))` of `H_(2)SO_(4)=oo` & `1.2xx10^(-2))`

A

`pH=1.62`

B

`pH=7.39`

C

Degree of hydrolysis `h=(1)/(sqrt(6))`

D

`h=3.4xx10^(-6)`

Text Solution

Verified by Experts

`1.2xx10^(-7)=(7.2xx10^(-2)alpha^(2))/(1-alpha)rArr 6alpha^(2)+alpha-1=0rArr alpha=(1)/(3)`
So `pH=-log ((0.072)/(3))=1.62`
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