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50 mL of 0.1 M NaOH is added to 60 mL of...

50 mL of 0.1 M NaOH is added to 60 mL of 0.15 M `H_(3)PO_(4)` solution `(K_(1), K_(2) " and " K_(3) " for " H_(3)PO_(4) " are " 10^(-3), 10^(-8) " and " 10^(-13)` respectively). The pH of the mixture would be about (log 2=0.3) :

A

`3.1`

B

`5.5`

C

`4.1`

D

`6.5`

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