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50mL of 0.05M Na(2)CO(3) is titrated aga...

`50mL` of `0.05M Na_(2)CO_(3)` is titrated against `0.1 M HCl` ,`pH` of the solution will be [Given :For `H_(2)CO_(3)` ,`pK_(a)=6.35,pK_(a)=10.33]`

A

`6.35`

B

`6.526`

C

`8.34`

D

`6.173`

Text Solution

Verified by Experts

`{:(,CO_(3)^(2-),+,H^(+),rarr,HCO_(3)^(-),),("Initial milli-moles",50xx0.05,,40xx0.1,,-,),("Final milli-moles",-,,1.5,,2.5,),(,HCO_(3)^(-),+,H^(+),rarr,H_(2)CO_(3),),("Initial milli-moles",2.5,,1.5,,-,),("Final milli-moles",-,,1,,1.5,):}`
` pH=pK_(a_(1))+log(([HCO_(3)^(-)])/([H_(2)CO_(3)]))=6.173`
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