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Let the colour of the indicator Hin (col...

Let the colour of the indicator Hin (coloueless) will be visible only when its ionised form (pink) is `25%` or more in a solution. Suppose Hin `(pK_(a)=9.0)` is added to a solution of pH=9.6 predict what will happen? (Take log `2=0.3`)

A

pink colour will be visible

B

pink colour will not be visible.

C

`%` of ionised form will be less then `25%`

D

`%` of ionised form will be more in `25%`

Text Solution

Verified by Experts

`HInrarrH^(+)+IN^(-)`
`K_(In)=([H^(+)][In^(-)])/([HIn])rArr ([In^(-)])/([HIn])=(K_(In))/([H^(+)])=(10^(-9))/(10^(-9.5))=10^(0.6)=4`
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