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Which chloride of I^(st) group basic rad...

Which chloride of `I^(st)` group basic radicals turns black on treatment with `NH_(3)`?

Text Solution

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The correct Answer is:
`Hg_(2)Cl_(2) + 2NH_(3) to ubrace (Hgdarr("black")+Hg(NH_(2))Cl darr("white"))_("Black")+NH_(4)^(+) +Cl^(-)`
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