`(2 sin (A-C) cos C- sin (A -2C)) /(2 sin (B-C) cos C -sin (B -2C) ) =sinA/sinB`

(2sin (AC) cos C-sin (A-2C)) / (2sin (BC) cos C-sin (B-2C)) = (sin A) / (sin B)

Prove that: (sin(A-C)+2sinA+sin(A+C)) / ("sin"("B"-"C")+2sinB+"sin"(B+C)) = (sinA)/(sinB)

Prove that: (sin(A-C)+2sinA+sin(A+C))/(sin(B-C)+2sinB+sin(B+C))=(sinA)/(sinB)

Prove that: (sin(A-C)+2sinA+sin(A+C))/(sin(B-C)+2sinB+sin(B+C))=(sinA)/(sinB)

If : A+B+C=pi, "then"" "sin ^(2) A +sin^(2)B - sin ^(2)C= A) 2 cos A * cos B * sin C B) 2 cos B * cos C * sin A C) 2 sin A * sin B * cos C D) 2 sin B * sin C * cos A

A+C=2B implies ( cos C - cos A )/( sin A - sin C )=

sin ^ (2) A + sin ^ (2) B-sin ^ (2) C = 2sin A sin B cos C

(sin(A-C)+2sinA+sin(A+C))/(sin(B-C)+2sinB+sin(B+C)) is equal to

(sin(A-C)+2sinA+sin(A+C))/(sin(B-C)+2sinB+sin(B+C)) is equal to

In any triangle ABC,sin^(2)A-sin^(2)B+sin^(2)C is always equal to (A) 2sin A sin B cos C(B)2sin A cos B sin C(C)2sin A cos B cos C(D)2sin A sin B sin C