A simple pendulum of length 1 m is oscillating with an angular frequency `10 rad//s`. The suopport of the down with a small angular frequecy of ` 1 rad//s` and an amplitude of `10^(-2)m` . The relative changes in the angular frequency of the pendulum is best given by.
A simple pendulum is oscillating with amplitue A and angular frequency omega At ratio of kinetic energy to potential energy is
A simple pendulum of length 1 m with a bob of mass m swings with an angular amplitude 30^(@) . Then (g= 9.8m//s^(2)
A body is executing the S.H.M. with an angular frequency of 2 rad/sec. Velocity of the body at 20 m displacement, when amplitude of motion is 60 m, is
A ball hung from a vertical spring oscillates in simple harmonic motion with an angular frequency of 2.6 rad/s and an amplitude of 0.075m. What is the maximum acceleration of the ball?
A body is executing simple harmonic motion with an angular frequency s rad/2 . The velocity of the body at 20 mm displacement, when the amplitude of motion is 60 mm , is
A simple pendulum is oscillating with an angular amplitude 60^@ . If mass of bob is 50 gram, then the tension in the string at mean position is (g = 10 ms^(-2))
A simple pendulum of length 40 cm oscillates with an angular amplitude of 0.04 rad. Find a. the time period b. the linear amplitude of the bob, c. The speed of the bob when the strig makes 0.02 rad with the vertical and d. the angular acceleration when the bob is in moemntary rest. Take g=10 ms^-2 .
A simple pendulum is oscillating with amplitude 'A' and angular frequency ' omega ' . At displacement 'x' from mean position, the ratio of kinetic energy to potential energy is
