The circuit showm below constains tow ideal diodes, each with a forward resistance of `50 Omega`. If the battery voltage is 6 V, the current through the `100 Omega` resistance ( in Amperes) is:
The circuit contains two diodes each with a forward resistance of 50Omega and with infinite reverse resistance. If the battery voltage is 6V, the current through the 120Omega resistance is_ mA
The circuit shown in the figure contains two diodes each with a forward resistance of 50 Omega and with infinite backward resistance. If the battery is 6 V, the current through the 100 Omega resistance (in ampere) is
The circuit shown in the figure contains two diodes each with a forward resistance of 30 Omega and with infinite backward resistance. If the battery is 3 V, the current through the 50 Omega resistance (in ampere) is
The circuit shown in figure (1) Contains two diodes each with a forward resistance of 50 ohm and with infinite reverse resistance. If the battery voltage is 6 V , the current through the 100 ohm resistance is. .
In the circuit, the current flowing through 10 Omega resistance
The circuit shown in the figure contains three diodes each with forward resistance of 50 ohms and with infinite backward resistance. If the battery voltage is 6 V, the current through the 100 ohm resistance is
The circuit shown in following figure contanis two diode D_(1) and D_(2) each with a forward resistance of 50 ohm and with infinite backward resistance. If the battery voltage is 6V , the current through the 100 ohm resistance (in amperes) is
In the given circuit,find the current through 6 Omega resistance
