The region between y =0 and y=d constains a magnetic field `vecB = Bvecz`. A particle of mass m and charge q enters of the region with a velocity `vecv = v veci`. If `d =(mv)/(2qB)` the acceleration of the charged particle at the point of its emergence at the other side is :
A charged particle of mass m and charge q enters a magnetic field B with a velocity v at an angle theta with the direction of B . The radius fo the resulting path is
A particle of mass m and charge Q moving with a velocity v enters a region on uniform field of induction B Then its path in the region is s
A particle of mass m and charge q enters a magnetic field B perpendicularly with a velocity v , The radius of the circular path described by it will be
AB and CD are two parallel planes perpendicular to the X axis. There is a uniform magnetic field (B) in the space between them directed in negative Z direction. Width of the region having field is d and rest of the space is hav- ing no field. A particle having mass m and charge + q enters the region with a velocity V making an angle q with the X direction as shown. (a) Find the values of d for which the particle will come out of the magnetic field crossing CD. (b) For d=((sqrt2-1)/(2))(mv)/(qB) and 0=(pi)/(6) find the angular deviation in the path of the particle. (c) Find the deviation in path of the particle if d=(5mv)/(4qB)(1-sin 0)
The figure shows two regions of uniform magnetic field of strengths 2B and 2B. A charged particle of mass m and charge q enters the region of the magnetic field with a velocity upsilon = (q B w)/(m) , where w is the width of each region of the magnetic field. The time taken by the particle to come out of the region of the magnetic field is
There exist uniform magnetic field vec(B)=-B_(0)hatk in region of space with 0ltxltd and 2dltxlt3d as shown in the figure. A positive charged particle of mass m and charge q is projected with velocity vec(v)=vhat(i) as shown in the figure. If radius of curvature of path of the charged particle in magnetic field is R(2dltRlt3d) then time elapse by charged particle in magnetic field regions is
There exist uniform magnetic field vec(B)=-B_(0)hatk in region of space with 0ltxltd and 2dltxlt3d as shown in the figure. A positive charged particle of mass m and charge q is projected with velocity vec(v)=vhat(i) as shown in the figure. If radius of curvature of path of the charged particle in magnetic field is R(2dltRlt3d) then time elapse by charged particle in magnetic field regions is
A particle of mass m having a charge q enters into a circular region of radius R with velocity v directed towards the centre. The strength of magnetic field is B . Find the deviation in the path of the particle.
