The mass and the diameter of a planet are three times the repective value for the Earth. The period of oscillation of a simple pendulum on the Earth is 2 s. The period of oscillation of the same pendulum on the planet would be:
The period of oscillation of a simple pendulum of constant length at earth surface is T. Its period inside a mine is C
The mass and diameter of a planet are twice those of earth. What will be the period of oscillation of a pendulum on this plenet. If is a second's pendulum on earth?
In a simple pendulum the period of oscillation (T) is related to the length of the pendulum (L) as
The period of oscillation of a simple pendulum of constant length at surface of the earth is T. Its time period inside mine will be
If the earth stops rotating then the time period of a simple pendulum at the equator would be
The time period of a simple pendulum is 0.2 s. What is its frequency of oscillation?
The time period of a simple pendulum at the centre of the earth is
