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The mass and the diameter of a planet a...

The mass and the diameter of a planet are three times the repective value for the Earth. The period of oscillation of a simple pendulum on the Earth is 2 s. The period of oscillation of the same pendulum on the planet would be:

A

`(sqrt(3))/(2)s`

B

`(2)/(sqrt(3))s`

C

`(3)/(sqrt(2))s`

D

`2sqrt(3)s`

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The radius and mass of some other planet are three times the respective values for Earth. If the period of oscillation of a simple pendulum on Earth is 2 s then what would be the period of oscillation of the same pendulum when it is taken to that other planet? (Answer in s) (Take sqrt(3) = 1.73 )

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Knowledge Check

  • The period of oscillation of a simple pendulum of constant length at earth surface is T. Its period inside a mine is C

    A
    Greater than T
    B
    Less than T
    C
    Equal to T
    D
    connot be compared

  • The mass and diameter of a planet are twice those of earth. What will be the period of oscillation of a pendulum on this plenet. If is a second's pendulum on earth?

    A
    `sqrt(2)s`
    B
    `2sqrt(2)s`
    C
    `(1)/sqrt(2)s`
    D
    `(1)/(2sqrt(2))s`

  • In a simple pendulum the period of oscillation (T) is related to the length of the pendulum (L) as

    A
    `L//T =`Constant
    B
    `L^(2)//T^(2) =` Constant
    C
    `L//T^(2) =`Constant
    D
    `LT =`Constant

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