Find no. of protons in 180 ml `H_(2)O` . Density of water =1 gm/ml.
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Mass of water=density `xx` volume=180g Moles of water `=(180)/(18)=10` 1 mol water has 10 mol protons 10 mol water has 100 mol protons 10 mol water has 100 `N_(A)` protons 10 mol water has `6.023xx10^(25)` protons
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