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A box contains 12xx10^(22) number of oxy...


A box contains `12xx10^(22)` number of oxygen atoms. Find moles of O-atoms? `(N_(A)=6xx10^(23))`

Text Solution

Verified by Experts

The correct Answer is:
`(##ALN_NC_CHM_MC_E01_001_A01##)`
`0.2
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Knowledge Check

  • The number of atoms in 0.1 mole of a triatomic gas is (N_(A)=6.02xx10^(23)"mol"^(-1))

    A
    `1.800xx10^(22)`
    B
    `6.026xx10^(22)`
    C
    `1.806xx10^(23)`
    D
    `3.600xx10^(23)`

  • the number of atoms in 0.1 mole of a triatomic gas is (N_(A)=6.02xx10^(23) mol^(-1))

    A
    `1.800xx10^(22)`
    B
    `6.026xx10^(22)`
    C
    `1.806xx10^(23)`
    D
    `3.600xx10^(23)`

  • The number of atoms in 0.1 mole of triatomic gas is: ( N_A=6.02xx10^(23)mol^(-1)) .

    A
    `6.026xx10^(22)`
    B
    `1.806xx10^(23)`
    C
    `3.600xx10^(23)`
    D
    `1.800xx10^(22)`

    • Similar Questions

    Explore conceptually related problems

    The number of atoms in 0.1 mol triatomic gas is: (N_(A)=6.02xx10^(23)"mol"^(-1))

    The number of atoms in 0.1 mol of a triatomic gas is (N_A = 6.02 xx 10^(23) mol^(-1) )

    The number of atoms in 0.1 mol of a tetraatomic gas is ( N_(A) = 6.02 xx 10^(23) mol^(-1) )

    Which of the following contain 9 xx 10^(23) oxygen atoms?

    A compound contains 7 carbon atoms, 2 oxygen atoms and 1.0 xx 10^(-23) gmof other elements. The molecular mass of compound is : (N_(A) = 6 xx 10^(23))

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