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1.5 gm mixture of SiO(2) and Fe(2)O(3) o...

1.5 gm mixture of `SiO_(2)` and `Fe_(2)O_(3)` on very strong heating leave a residue weighting 1.46 gm. The reaction responsible for loss of weight is
`Fe_(2)O_(3)(s) to Fe_(3)O_(4)(s) +O_(2)(g)`
What is the percentage by mass of `Fe_(2)O_(2)` in original sample.

Text Solution

Verified by Experts

`3Fe_(2)O_(3) to 2Fe_(3)O_(4) + (1)/(2)O_(2)`
`3xx160 " "(1)/(2)xx32`
`=480 gm to " "=16 gm`
loss of 16 gm `to 480` gm `Fe_(2)O_(3)`
loss of 0.04 gm `to 0.04xx(480)/(16)=1.2` gm `Fe_(2)O_(3)`
`%` by mass `=(1.2)/(1.5)xx100=80%`
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