How many grams `H_(2)SO_(4)` can be obtained from `1320gm PbS` as per reaction sequence ?. `2PbS+O_(2)rarr2PbO+2SO_(2)` `3SO_(2)+2HNO_(3)+2H_(2)Orarr3H_(2)SO_(4)+2NO` `["At mass" Pb = 208. S = 32]`.
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Moles of PbS=`(1320)/(240)=5.5` mol Moles of `SO_(2)=5.5` mol =moles of `H_(2)SO_(4)` Mass of `H_(2)SO_(4)=5.5xx98=539` gm [When amount of only one reactant is given generaly other is assumed in excess.
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