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What weight of AgCl will be precipitated...

What weight of `AgCl` will be precipitated when a solution containing `4.77 g NaCl` is added to a solution of `5.77 g` of `AgNO_(3)`.

Text Solution

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The correct Answer is:
4.879 gm
`L.R`
`darr`
`AgNO_(3)+NaCl to NaNO_(3)+AgNO_(3)`
`5.77 gm " " 4.77 gm `
` 0.034 "mole" " " 0.082 "mole"`
wt. of `AgCl=0.034xx143.5=4.879 gm`
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