Home
Class 12
CHEMISTRY
500 mL, 0.2"M NA"(2)SO(4) solution is mi...

500 mL, `0.2"M NA"_(2)SO_(4)` solution is mixed with 100 mL, `17.1%(w//v)Al_(2)(SO_(4))_(3)` solution and resulting solution is diluted to 5 times. Find the molarity of `SO_(4)^(-2)` ions in the final solution.
[Atomic mass of Al = 27, S = 32, Na = 23]

A

`(1)/(12)M`

B

`(5)/(12)M`

C

`(7)/(5)M`

D

`(12)/(5)M`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

If 100 mL "of" 1 M H_(2) SO_(4) solution is mixed with 100 mL of 98% (W//W) of H_(2)SO_(4) solution (d = 0.1 g mL^(-1)) , then

100ml of 2.45 % (w//v) H_(2)SO_(4) solution is mixed with 200ml of 7% (w//w) H_(2)SO_(4) solution ("density" = 1.4 gm//ml) and the mixture is diluted to 500ml . What is the molarity of the diluted solution ?

If 200ml of 0.2 M BaCl_(2) solution is mixed with 500ml of 0.1M Na_(2)SO_(4) solution. Calculate osmotic pressure of resulting solutions?

A solution containing 200 ml 0.5 M KCl is mixed with 50 ml 19% w/v MgCl_(2) and resulting solution is dilute 8 times. Molarity of chloride ion is final solution is :

300 ml, 2 M H_(2)SO_(4) solution is mixed with 200 ml, 2 M Ba (OH)_2) solution then find final molarity of sulphate ion in diluted to 4 times. ( BaSO_(4) formed is precipitated)

100 ml of 0.2"M H"_(2)SO_(4) solution is mixed with 400ml of 0.05"M Ba"_(3)(PO_(4))_(2) . Calculate the concentration of [Ba^(+2)] ion in resulting solution.

500 mL of 0.250 M Na_(2)SO_(4) solution is treated with 15.00 g of BaCl_(2) . Moles of BaSO_(4) formed are

100mL, 3% (w/v) NaOH solution is mixed with 100 ml, 9% (w/v) NaOH solution. The molarity of final solution is

100 ml of 0.3 M HCl solution is mixed with 200 ml of 0.3 M H_(2)SO_(4) solution. What is the molariyt of H^(+) in resultant solution ?