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Suppose velocity of a cricket ball hit b...

Suppose velocity of a cricket ball hit by a batsman is given by
`vec(v) = (2hati +6hatj + (@0-10t)hatk)m//s`
Find the time (t) the acceleration of the ball is perpendicular to its velocity.

A

1s

B

2s

C

3s

D

4s

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Knowledge Check

  • The position vector of a particle at time t is given by vecr=2t hati+5t hatj+4sin omegat hatk where omega is a constant.Answer the following questions Velocity vector is perpendicular to …….vector

    A
    `2hati+4hatj`
    B
    `3hati+2hatj`
    C
    `5hati-2hatj`
    D
    None
  • The position vector of a aprticle is given as vecr=(t^2-4t+6)hati+(t^2)hatj . The time after which the velocity vector and acceleration vector becomes perpendicular to each other is equal to

    A
    1 sec
    B
    2 sec
    C
    1.5 sec
    D
    not possible
  • An object has velocity vec v = (i+2hatj+3hatk)m//s . A constant acceleration of the object for which its speed starts decreasing is:

    A
    `vec a= 2hatj+hatk`
    B
    `veca = 7hati-6hatj-hatk`
    C
    `veca = 7hati+hatj-hatk`
    D
    `veca = 3hati-4hatj+2hatk`
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    The velocity of a body of mass 2 kg as a function of t is given by upsilon(t) = 2t hati + t^(2) hatj Find the momentum and force acting on it at time t = 2 s .

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