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find the sum of the series upto n terms...

find the sum of the series upto n terms `1+(1+2)/2+(1+2+3)/3+(1+2+3+4)/4+......`

Text Solution

Verified by Experts

The correct Answer is:
`(n(n + 3))/(4)`
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Knowledge Check

  • Find the sum to n terms of the series + (1+2) + (1+2+3) + (1+2+ 3+ 4) + ….:

    A
    `(n(n+1)(2n+1))/(6)`
    B
    `(n(n+1)(n+2))/(6)`
    C
    `(n(n+1)(n+2))/(12)`
    D
    `(n(n+1))/(2)`

  • Find the sum to first n terms : 1+2/3 + 2/(3^2) + 4/(3^3) +….

    A
    a)`3/4 - (3+2n)/(4(3^(n-1)))`
    B
    b)`9/4 - 3/4 [(3+2n)/(3^n)]`
    C
    c)`2n - (1/n)^2`
    D
    d)none of these

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