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Let a1,a2,a3,...... be an A.P. such that...

Let `a_1,a_2,a_3,......` be an A.P. such that `[a_1+a_2+......+a_p]/[a_1+a_2+a_3+......+a_q]=p^3/q^3` ; `p!=q`.Then `a_6/a_[21]` is equal to:

A

`(121)/(1861)`

B

`(11)/(41)`

C

`(121)/(1681)`

D

`(41)/(11)`

Text Solution

Verified by Experts

The correct Answer is:
C
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