Given sum of the first `n` terms of an A.P is `2n + 3n^(2)`. Another A.P. is formed with the same first term and double of the common difference, the sum of `n` terms
A
`n + 4n^(2)`
B
`n^(2) + 4n`
C
`3n + 2n^(2)`
D
`6n^(2) - n`
Text Solution
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The correct Answer is:
D
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