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If sin^4 alpha + 4 cos^4 beta + 2 = 4sqr...

If `sin^4 alpha + 4 cos^4 beta + 2 = 4sqrt2 sin alpha cos beta ; alpha, beta in [0,pi],` then `cos(alpha+beta) - cos(alpha - beta)` is equal to :

A

0

B

`-sqrt2`

C

`-1`

D

`sqrt2`

Text Solution

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The correct Answer is:
B
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