A bird with mass m parches at the middle of a strectched string Show that the tension in the string is give by `T=(mg)/(2sintheta).` Assuming that each half of the string is straight.

Explanation

Initial position of wire = AOB. Final position of wire = ACB Let `theta` be the angle made by wire with horizontal, which is very small. Reasolving tension T of string in horizonts cancel while vertical components add and balance the weight.
For equilibrium `2T sintheta=W=mgimpliesT=(W)/(2sintheta)=mg//2sintheta`