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At a certain time velocities of 1 and 2 ...

At a certain time velocities of `1` and `2` both are `1m//s` upwards. Find the velocity of `3` at that moment

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`x_(1)+x_(4)=l_(1)` (length of first string)
`x_(2)-x_(4)+x_(3)-x_(3)-x_(4)=l_(2)` (length of second string)
`impliesv_(1)+v_(4)=0&v_(2)+v_(3)-2V_(4)=0`
`impliesv_(2)+v_(3)+2v_(1)=0`
Thinking upward direction s positive
`v_(1)=v_(2)=1`
`so 1+v_(3)+2xx1=0impliesv_(3)= -3 ms^(-1)`
i.e., velocity of block 3 is `3 ms^(-1)` downwards.
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