Home
Class 12
PHYSICS
A block of mass 2 kg rests on an incline...

A block of mass 2 kg rests on an inclined plane which makes an angle of `30^(@)` with the horizontal. The coefficient of friction between the block and the surfcae is `sqrt(3//2)`. (i) What force should be applied on the block so that it moves down without any acceleration ? (ii) What force should be applied on the block so that it moves up without any acceleration ? (iii) Calculate the ratio of the powers in the above two cases if the block moves with uniform speed in both the cases.

Text Solution

Verified by Experts

Make a 'free-body' diagram of the block. The the force of friction opposite of the direction of motion.
(i) Project forces along and perpendicular to the plane
`{:("perpendicular to plane",N=mg cos theta),("along the plane",F+mg sintheta-f=0):}`
(`because` there is no acceleration along the plane)
`F+mg sintheta-muN=0impliesFmgsintheta=mumgcostheta`
`F=mg(mucostheta-sintheta)=2xx9.8"("(sqrt3)/(2)cos30^(@)-sin30^(@)")"`
`=19.6"("(sqrt3)/(2)xx(sqrt3)/(2)-1/2")"=19.6"("(3)/(4)-(1)/(2)")"=4.9N`

(ii) This time the direction of F is reversed and that of the frictional force is also reversed.
`thereforeN=mgcostheta,F=mgsintheta+f`
`impliesF=mg(mucostheta+sintheta)=19.6"("3/4+1/2")"=24.5N`
Promotional Banner

Topper's Solved these Questions

  • NEWTON'S LAWS OF MOTION & FRICTION

    ALLEN|Exercise EXERCISE (S-1)|26 Videos
  • NEWTON'S LAWS OF MOTION & FRICTION

    ALLEN|Exercise EXERCISE (S-2)|9 Videos
  • MOTION IN A PALNE

    ALLEN|Exercise SOLVED EXAMPLE|28 Videos
  • NEWTONS LAWS OF MOTION

    ALLEN|Exercise EXERCISE-III|28 Videos

Similar Questions

Explore conceptually related problems

A block of mass 2kg rests on a rough inclined plane making an angle of 30^@ with the horizontal. The coefficient of static friction between the block and the plane is 0.7. The frictional force on the block is

A block of mass m slides down an inclined plane which makes an angle theta with the horizontal. The coefficient of friction between the block and the plane is mu . The force exerted by the block on the plane is

A block rests on a rough inclined plane making an angle of 30^@ with the horizontal. The coefficient of static friction between the block and the plane is 0.8. If the frictional force on the block is 10N, the mass of the block (in kg) is

A block rests on a rough inclined plane making an angle of 30° with the horizontal. The coefficient of static friction between the block and inclined plane is 0.8. If the frictional force on the block is 10 N, the mass of the block is

A block of mass 5 kg rests on a inclined plane at an angle of 30^(@) with the horizontal. If the block just begins to slide, then what is the coefficient of static friction between the block and the surface?

A block is lying on an inclined plane which makes 60^(@) with the horizontal. If coefficient of friction between block and plane is 0.25 and g=10m//s^2 , , then acceleration of the block when it moves along the plane will be

A block of mass m = 2kg is resting on a inclined plane of inclination 30^(@) as shown in figure The coefficient of friction between the block and the plane is mu = 0.5 what minimum force F (in newton) should be applied perpendicular to the plane on the block so that the does not slip on the plane?

A block of mass m is at rest on a rough inclined plane of angle of inclination theta . If coefficient of friction between the block and the inclined plane is mu , then the minimum value of force along the plane required to move the block on the plane is

A block of mass m is placed at rest on an inclination theta to the horizontal.If the coefficient of friction between the block and the plane is mu , then the total force the inclined plane exerts on the block is