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A block of 1 kg is stopped against a wal...

A block of 1 kg is stopped against a wall by applying a force F perpendicular to the wall. If `mu=0.2` then minimum value of F will be

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The situation is shown in fig. The forces acting on the book are For book to be a rest it is essential that Mg = `f_(s)`
But `f_(smax)=mu_(s)N " "and N=F`
`thereforeMg=mu_(s)FimpliesF=(Mg)/(mu_(s))=(1xx9.8)/(0.2)=49N`
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