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A block of mass m lies on wedge of mass ...

A block of mass m lies on wedge of mass Mas shown in figure. Find the minimum friction coeffcient required between wedge Mand ground so that it does not move while block m slips down on it.

Text Solution

Verified by Experts

The correct Answer is:
`mu_(min)=(minthetacostheta)/(mcos^(2)theta+M)`
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A block of mass mlies on wedge of mass M as shown in figure. Answer following parts separately. (a)Withwhat minium acceleration must the wedge be moved towards right horizontally so that block m falls freely. ( b)Find the minimum friction coefficient required between wedge M and ground so that it does not move while block m slips down on it.

A block of mass m lies on wedge of mass. Mas shown in figure. With what minimum acceleration must the wedge be moved towared right horizontally so that block m falls freely.

Knowledge Check

  • A block of mass 1 kg is placed on a wedge shown in figure. Find out minimum coefficient of friction between wedge and block to stop the block on it.

    A
    0.6
    B
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    C
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    D
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  • A wedge of mass 2m and a cube of mass m are shown in figure. Between cube and wedge, there is no friction. The minimum coefficient of friction between wedge and ground so that wedge does not move is

    A
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    B
    `0.20`
    C
    0.25
    D
    `0.50`

  • a Block of mass m is placed on a wedge of mass M there is no friction between the block and the wedge .The minmum coefficient of friction between the wedge and the gound so that wedge does not move is,

    A
    `(mcos^(2)theta)/(M+mcos^(2) theta)`
    B
    `(msin^(2)theta)/(M+mcos^(2) theta)`
    C
    `(mcos thetasintheta)/(M+mcos^(2) theta)`
    D
    `(mcos thetasintheta)/(M+msin^(2) theta)`

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