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If vec(A)=2hati+hatj+hatk " and " vecB=1...

If `vec(A)=2hati+hatj+hatk " and " vecB=10hati+5hatj+5hatk`, if the magnitude of component of `(vec(B)-vec(A))` along `vec(A)` is `4sqrt(x)`. Then x will be .

Text Solution

Verified by Experts

The correct Answer is:
6
`r=vec(B)-vec(A)=4(2hati+hatj+hatk)`
`r cos theta =(vecr.vec(A))/(|A|)=(4(4+1+1))/(sqrt(6))=4sqrt(6)`
`x=6`
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