The distance moved by a particle in time from centre of ring under the influence of its gravity is given by `x=a sin omegat` where a and `omega` are constants. If `omega` is found to depend on the radius of the ring (r), its mass (m) and universal gravitation constant (G), find using dimensional analysis an expression for `omega` in terms of r, m and G.

Answer

`omega=Ksqrt((GM)/(r^(3)))`