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In a certain system of units, 1 unit of ...

In a certain system of units, 1 unit of time is 5 sec, 1 unit of mass is 20 kg and 1 uint of length is 10m. In this system, one unit of power will correspond to :-

A

16 watts

B

`(1)/(16)` watts

C

25 watts

D

none of these.

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The correct Answer is:
To find the unit of power in the given system of units, we need to follow these steps: 1. **Identify the given units in the new system:** - 1 unit of time = 5 seconds - 1 unit of mass = 20 kg - 1 unit of length = 10 meters 2. **Recall the formula for power:** \[ \text{Power} = \frac{\text{Work done}}{\text{Time}} \] Work done (W) is given by: \[ W = \text{Force} \times \text{Displacement} \] Force (F) is given by: \[ F = \text{Mass} \times \text{Acceleration} \] 3. **Substitute the expressions into the power formula:** \[ \text{Power} = \frac{\text{Mass} \times \text{Acceleration} \times \text{Displacement}}{\text{Time}} \] 4. **Convert each quantity to the given units:** - Mass: 1 unit of mass = 20 kg - Acceleration: \(\text{Acceleration} = \frac{\text{Length}}{\text{Time}^2}\) \[ \text{Acceleration} = \frac{10 \text{ meters}}{(5 \text{ seconds})^2} = \frac{10}{25} \text{ m/s}^2 = 0.4 \text{ m/s}^2 \] - Displacement: 1 unit of length = 10 meters - Time: 1 unit of time = 5 seconds 5. **Substitute these values into the power formula:** \[ \text{Power} = \frac{20 \text{ kg} \times 0.4 \text{ m/s}^2 \times 10 \text{ meters}}{5 \text{ seconds}} \] 6. **Calculate the power:** \[ \text{Power} = \frac{20 \times 0.4 \times 10}{5} \text{ watts} \] Simplify the expression: \[ \text{Power} = \frac{80}{5} \text{ watts} = 16 \text{ watts} \] Therefore, one unit of power in the given system of units corresponds to 16 watts.
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