Ethyl acetate on reaction with excess of methyl magnesium chloride and dil `H_(2)SO_(4)` gives .

Options

A. dimethyl ketone
B. iso propyl alcohol
C. ethyl aceto acetate
D. t - butyl alcohol

Explanation

To solve the question regarding the reaction of ethyl acetate with excess methyl magnesium chloride and dilute H₂SO₄, we can follow these steps:

### Step 1: Identify the Reactants
We have ethyl acetate (C₂H₅COOCH₃) and excess methyl magnesium chloride (CH₃MgCl). Methyl magnesium chloride is a Grignard reagent, which acts as a nucleophile.

**Hint:** Recognize the structure of ethyl acetate and the role of Grignard reagents in nucleophilic addition reactions.

### Step 2: Nucleophilic Attack
The nucleophilic carbon (from the methyl group of the Grignard reagent) will attack the carbonyl carbon of ethyl acetate. This results in the formation of a tetrahedral intermediate.

**Hint:** The carbonyl carbon is electrophilic, making it susceptible to nucleophilic attack.

### Step 3: Formation of the Tetrahedral Intermediate
The tetrahedral intermediate can be represented as follows:
- The oxygen of the carbonyl group becomes negatively charged (O⁻).
- The structure now includes a new bond from the methyl group to the carbonyl carbon.

**Hint:** Remember that the tetrahedral intermediate is a key step in nucleophilic addition reactions.

### Step 4: Collapse of the Tetrahedral Intermediate
The tetrahedral intermediate will collapse, leading to the formation of a ketone (in this case, 3-methylbutan-2-one) and the release of the ethoxy group (C₂H₅O⁻) as a leaving group.

**Hint:** Understand that the collapse of the tetrahedral intermediate regenerates the carbonyl functionality.

### Step 5: Second Nucleophilic Attack
Since we have excess methyl magnesium chloride, the newly formed ketone (3-methylbutan-2-one) will again be attacked by another molecule of methyl magnesium chloride. This will form a new tetrahedral intermediate.

**Hint:** Excess Grignard reagent means that the ketone can be further reacted.

### Step 6: Hydrolysis
After the second nucleophilic attack, hydrolysis with dilute H₂SO₄ will convert the intermediate into a tertiary alcohol. The final product will be 2-methyl-2-propanol (tert-butanol).

**Hint:** Hydrolysis is crucial for converting the Grignard adduct into the final alcohol product.

### Final Answer
The final product of the reaction of ethyl acetate with excess methyl magnesium chloride and dilute H₂SO₄ is **tert-butanol (2-methyl-2-propanol)**.

### Summary of Steps:
1. Identify reactants (ethyl acetate and Grignard reagent).
2. Nucleophilic attack on the carbonyl carbon.
3. Formation of tetrahedral intermediate.
4. Collapse of the intermediate to form a ketone.
5. Second nucleophilic attack by Grignard reagent.
6. Hydrolysis to form tertiary alcohol.