If the point charge is now moved to a distance 'd' form the centre of the square and the side of the square is doubled explain how the electric flux will be affected.

Explanation

To solve the problem, we need to analyze how the electric flux changes when a point charge is moved and the side length of the square is doubled. We will use Gauss's Law, which states that the electric flux (Φ) through a closed surface is proportional to the charge (Q) enclosed by that surface, given by the formula:

\[ \Phi = \frac{Q}{\epsilon_0} \]

where \( \epsilon_0 \) is the permittivity of free space.

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