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The photoelectric cut off voltage in a c...

The photoelectric cut off voltage in a certain experiment is 1.5V. What is the maximum kinetic energy of photoelectrons emitted? `e=1.6xx10^(-19)C`.

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K.E. = eV , / K.E = 1.5 e Joule
`=1.5 xx 1.6 xx 10^(-19)J`
`=2.4xx10^(-19)J`
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