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Evaluate ((3)/(8))^(-2) xx ((4)/(5))^(-3...

Evaluate `((3)/(8))^(-2) xx ((4)/(5))^(-3).`

A

`(121)/(9)`

B

`(125)/(9)`

C

`(155)/(9)`

D

`(15)/(9)`

Text Solution

AI Generated Solution

The correct Answer is:
To evaluate the expression \(\left(\frac{3}{8}\right)^{-2} \times \left(\frac{4}{5}\right)^{-3}\), we will follow these steps: ### Step 1: Apply the Negative Exponent Rule The negative exponent rule states that \(a^{-m} = \frac{1}{a^m}\). Therefore, we can rewrite the expression: \[ \left(\frac{3}{8}\right)^{-2} = \frac{1}{\left(\frac{3}{8}\right)^{2}} \quad \text{and} \quad \left(\frac{4}{5}\right)^{-3} = \frac{1}{\left(\frac{4}{5}\right)^{3}} \] So, we can rewrite the original expression as: \[ \frac{1}{\left(\frac{3}{8}\right)^{2}} \times \frac{1}{\left(\frac{4}{5}\right)^{3}} = \frac{1}{\left(\frac{3}{8}\right)^{2} \times \left(\frac{4}{5}\right)^{3}} \] ### Step 2: Calculate the Powers Now we will calculate \(\left(\frac{3}{8}\right)^{2}\) and \(\left(\frac{4}{5}\right)^{3}\): \[ \left(\frac{3}{8}\right)^{2} = \frac{3^{2}}{8^{2}} = \frac{9}{64} \] \[ \left(\frac{4}{5}\right)^{3} = \frac{4^{3}}{5^{3}} = \frac{64}{125} \] ### Step 3: Multiply the Results Now we will multiply these two results: \[ \left(\frac{3}{8}\right)^{2} \times \left(\frac{4}{5}\right)^{3} = \frac{9}{64} \times \frac{64}{125} \] ### Step 4: Simplify the Expression When multiplying fractions, we multiply the numerators and the denominators: \[ \frac{9 \times 64}{64 \times 125} = \frac{9}{125} \] ### Step 5: Write the Final Result Now, substituting back into our expression: \[ \frac{1}{\left(\frac{3}{8}\right)^{2} \times \left(\frac{4}{5}\right)^{3}} = \frac{1}{\frac{9}{125}} = \frac{125}{9} \] Thus, the final answer is: \[ \frac{125}{9} \] ---
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