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How many bricks, each measuring 25 cm xx...

How many bricks, each measuring `25 cm xx 1.25 cm xx 6 cm`, will be needed to build a wall 8 m long, 6m high and 22.5 cm thick?

A

5600

B

6000

C

6400

D

7200

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The correct Answer is:
To solve the problem of how many bricks are needed to build a wall with the given dimensions, we will follow these steps: ### Step 1: Convert all measurements to the same unit The dimensions of the wall are given in meters and centimeters. To make calculations easier, we will convert everything to centimeters. - Length of the wall = 8 m = 8 × 100 cm = 800 cm - Height of the wall = 6 m = 6 × 100 cm = 600 cm - Thickness of the wall = 22.5 cm (already in cm) ### Step 2: Calculate the volume of the wall The volume of a rectangular prism (which is the shape of the wall) is given by the formula: \[ \text{Volume} = \text{Length} \times \text{Height} \times \text{Thickness} \] Substituting the values we have: \[ \text{Volume of the wall} = 800 \, \text{cm} \times 600 \, \text{cm} \times 22.5 \, \text{cm} \] ### Step 3: Calculate the volume of one brick The dimensions of one brick are given as: - Length = 25 cm - Width = 1.25 cm - Height = 6 cm Using the same volume formula: \[ \text{Volume of one brick} = 25 \, \text{cm} \times 1.25 \, \text{cm} \times 6 \, \text{cm} \] ### Step 4: Calculate the number of bricks needed To find the number of bricks required, we divide the volume of the wall by the volume of one brick: \[ \text{Number of bricks} = \frac{\text{Volume of the wall}}{\text{Volume of one brick}} \] ### Step 5: Perform the calculations 1. Calculate the volume of the wall: \[ \text{Volume of the wall} = 800 \times 600 \times 22.5 = 10800000 \, \text{cm}^3 \] 2. Calculate the volume of one brick: \[ \text{Volume of one brick} = 25 \times 1.25 \times 6 = 187.5 \, \text{cm}^3 \] 3. Calculate the number of bricks: \[ \text{Number of bricks} = \frac{10800000}{187.5} \approx 57600 \] ### Final Answer The number of bricks needed to build the wall is approximately **57,600 bricks**. ---
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RS AGGARWAL-VOLUME AND SURFACE AREA OF SOLIDS-EXERCISE 20 C OBJECTIVE QUESTIONS
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  14. The diagonal of a cube is 9sqrt(3) cm long. Its total surface area is

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  15. If each side of a cube is doubled then its volume

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