The correct order of N-O bond lengths in NO, `NO_2^- , NO_3^-` and `N_2O_4` is

Options

A. `N_2O_4 gt NO_2^(-) gt NO_3^(-) gt NO`
B. `NO gt NO_3^(-) gt N_2O_4 gt NO_2^-`
C. `NO_3^(-) gt NO_2^(-) gt N_2O_4 gt NO`
D. `NO gt N_2O_4 gt NO_2^(-) gt NO_3^(-)`

Answer

C

Explanation

As the bond order increases, bond length decreases and bond order is highest for NO, i.e. 2.5 and least for `NO_3^-` , i.e. 1.33. So, the order of bond length is

`underset"1.33"(NO_3^-) gt underset"1.5"(NO_2^-)gt underset"1.5"(N_2O_4)gt underset"2.5"(NO)`