What is the Van’t Hoff factor in `K_(4) [Fe(CN)_(6)]` and `BaCl_(2)` ?

Explanation

To find the Van’t Hoff factor (i) for the compounds \( K_4[Fe(CN)_6] \) and \( BaCl_2 \), we need to determine how many particles each compound dissociates into when dissolved in solution.

### Step-by-Step Solution:

1. **Identify the dissociation of \( K_4[Fe(CN)_6] \)**:
- The formula \( K_4[Fe(CN)_6] \) indicates that there are 4 potassium ions (K\(^+\)) and one complex ion \([Fe(CN)_6]^{4-}\).
- When \( K_4[Fe(CN)_6] \) dissociates in solution, it produces:
- 4 \( K^+ \) ions
...