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When 0.1 mol CoCl(3)(NH(3))(5) is treate...

When 0.1 mol `CoCl_(3)(NH_(3))_(5)` is treated with excess of `AgNO_(3)`, 0.2 mole of AgCl are obtained. The conductivity of solution will correspond to

A

1:3 electrolyte

B

1:2 electrolyte

C

1:1 electrolyte

D

3:1 electrolyte

Text Solution

Verified by Experts

The correct Answer is:
B
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